What is the tangent of f(x)=sqrt(2x),(2,2) ?

The tangent of f(x)=sqrt(2x),(2,2) is y= 1/2 x+1

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tangent of f(x)=sqrt(2x),(2,2)

tangent of

f (x) = 2 x, (2, 2)

y = \frac{1}{2} x + 1

Solution steps

Find the slope of

f (x) = 2 x : \frac{df ( x )}{d x} = \frac{1}{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(2, 2) : y = \frac{1}{2} x + 1

y = \frac{1}{2} x + 1

\frac{2}{s ^{2} ( s ^{2} - 2 s + 5 )}

\int x cos (x^{2} + 4) d x

y = \frac{5}{x}

\frac{d}{d x} (e^{2 x - 2})

x^{2} - 16 ln (x^{2})

What is the tangent of f(x)=sqrt(2x),(2,2) ?
The tangent of f(x)=sqrt(2x),(2,2) is y= 1/2 x+1