What is the integral from 2 to infinity of e^{-7x} ?

The integral from 2 to infinity of e^{-7x} is 1/(7e^{14)}

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integral from 2 to infinity of e^{-7x}

\int_{2}^{\infty} e^{- 7 x} d x

\frac{1}{7 e ^{14}}

Decimal

1.1879 E - 7

Solution steps

\int_{2}^{\infty} e^{- 7 x} d x

Compute the indefinite integral:

\int e^{- 7 x} d x = - \frac{1}{7} e^{- 7 x} + C

Compute the boundaries:

\int_{2}^{\infty} e^{- 7 x} d x = 0 - (- \frac{1}{7 e ^{14}})

= 0 - (- \frac{1}{7 e ^{14}})

Simplify

= \frac{1}{7 e ^{14}}

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What is the integral from 2 to infinity of e^{-7x} ?
The integral from 2 to infinity of e^{-7x} is 1/(7e^{14)}