What is the sum from k=0 to infinity of (4/5)^k ?

The sum from k=0 to infinity of (4/5)^k is 5

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sum from k=0 to infinity of (4/5)^k

k = 0 \sum \infty (\frac{4}{5})^{k}

5

Solution steps

k = 0 \sum \infty (\frac{4}{5})^{k}

Apply Series Geometric Test:

5

= 5

- \frac{1}{( x + 1 ) ^{2}}

\int (\frac{e ^{x}}{x}) d x

n = 1 \sum \infty \frac{1 ^{n}}{n + 1}

\frac{d}{d x} (\frac{x ^{2} + 1}{( x + 1 ) ^{3}})

\frac{\partial}{\partial x} (x y + \frac{2}{x} + \frac{4}{y})

What is the sum from k=0 to infinity of (4/5)^k ?
The sum from k=0 to infinity of (4/5)^k is 5