What is the derivative of (ln(4x)^2) ?

The derivative of (ln(4x)^2) is (2ln(4x))/x

What is the first derivative of (ln(4x)^2) ?

The first derivative of (ln(4x)^2) is (2ln(4x))/x

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\frac{d}{d x} ((ln (4 x))^{2})

\frac{2 ln ( 4 x )}{x}

Solution steps

\frac{d}{d x} ((ln (4 x))^{2})

Apply the chain rule:

2 ln (4 x) \frac{d}{d x} (ln (4 x))

= 2 ln (4 x) \frac{d}{d x} (ln (4 x))

\frac{d}{d x} (ln (4 x)) = \frac{1}{x}

= 2 ln (4 x) \frac{1}{x}

Simplify

2 ln (4 x) \frac{1}{x} : \frac{2 ln ( 4 x )}{x}

= \frac{2 ln ( 4 x )}{x}

49 y^{^{''}} + 112 y^{^{'}} + 64 y = 0

\int (4 x^{2} - 2 x - 2) d x

\int 25 + x d x

\frac{d}{d x} (e^{3 x} + e^{- 2 x})

y^{^{''}} + 6 y^{^{'}} + 15 y = 0

What is the derivative of (ln(4x)^2) ?
The derivative of (ln(4x)^2) is (2ln(4x))/x
What is the first derivative of (ln(4x)^2) ?
The first derivative of (ln(4x)^2) is (2ln(4x))/x