What is the integral from 0 to infinity of 6sin^2(x) ?

The integral from 0 to infinity of 6sin^2(x) is diverges

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integral from 0 to infinity of 6sin^2(x)

\int_{0}^{\infty} 6 sin^{2} (x) d x

diverges

Solution steps

\int_{0}^{\infty} 6 sin^{2} (x) d x

Compute the indefinite integral:

\int 6 sin^{2} (x) d x = 3 (x - \frac{1}{2} sin (2 x)) + C

Compute the boundaries:

\int_{0}^{\infty} 6 sin^{2} (x) d x =

diverges

= diverges

x \to - 1 lim (2 x + 6)

\int (\frac{1}{x ^{11}}) d x

\int csc^{3} (2 x + 1) d x

(2.3) (8.6)

\int \frac{- 4 x ^{3}}{x ^{2} + 9} d x

What is the integral from 0 to infinity of 6sin^2(x) ?
The integral from 0 to infinity of 6sin^2(x) is diverges