What is the limit as x approaches 2 of ln(4-x^2) ?

The limit as x approaches 2 of ln(4-x^2) is Does not exist

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limit as x approaches 2 of ln(4-x^2)

x \to 2 lim (ln (4 - x^{2}))

Does not exist

Solution steps

x \to 2 lim (ln (4 - x^{2}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 2 + lim (ln (4 - x^{2})) =

Does not exist

x \to 2 - lim (ln (4 - x^{2})) = - \infty

= Does not exist

\int e^{x} + x d x

x \to 0 lim (\frac{2}{x ^{2}})

\frac{d}{d x} (\frac{x + 4}{7 x ^{2} e ^{x}})

\frac{d}{d x} (8 ln (cos (x)))

\int \frac{( 4 + 10 x )}{7 + 4 x + 5 x ^{2}} d x

What is the limit as x approaches 2 of ln(4-x^2) ?
The limit as x approaches 2 of ln(4-x^2) is Does not exist