What is the solution for y^{''}+7y^'+6y=0 ?

The solution for y^{''}+7y^'+6y=0 is y=c_{1}e^{-t}+c_{2}e^{-6t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+7y^'+6y=0

y^{^{''}} + 7 y^{^{'}} + 6 y = 0

y = c_{1} e^{- t} + c_{2} e^{- 6 t}

Solution steps

y^{''} (t) + 7 y^{'} (t) + 6 y = 0

Solve linear ODE:

y = c_{1} e^{- t} + c_{2} e^{- 6 t}

y = c_{1} e^{- t} + c_{2} e^{- 6 t}

f (x) = 2 (x)^{3} ln (x)

x \to - 2 lim (\frac{x ^{2} + 4}{x + 2})

y = - x^{2} + 10, y = - 1.5 x + 7

\frac{d}{d x} (\frac{x ^{2} - x ^{4}}{8})

\frac{d}{d x} (x - arcsin (x))

What is the solution for y^{''}+7y^'+6y=0 ?
The solution for y^{''}+7y^'+6y=0 is y=c_{1}e^{-t}+c_{2}e^{-6t}