What is the integral of (1-x)/(x^3) ?

The integral of (1-x)/(x^3) is -1/(2x^2)+1/x+C

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integral of (1-x)/(x^3)

\int \frac{1 - x}{x ^{3}} d x

- \frac{1}{2 x ^{2}} + \frac{1}{x} + C

Solution steps

\int \frac{1 - x}{x ^{3}} d x

Expand

\frac{1 - x}{x ^{3}} : \frac{1}{x ^{3}} - \frac{1}{x ^{2}}

= \int \frac{1}{x ^{3}} - \frac{1}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x ^{3}} d x - \int \frac{1}{x ^{2}} d x

\int \frac{1}{x ^{3}} d x = - \frac{1}{2 x ^{2}}

\int \frac{1}{x ^{2}} d x = - \frac{1}{x}

= - \frac{1}{2 x ^{2}} - (- \frac{1}{x})

Simplify

= - \frac{1}{2 x ^{2}} + \frac{1}{x}

Add a constant to the solution

= - \frac{1}{2 x ^{2}} + \frac{1}{x} + C

\frac{d y}{d x} = (x - 18)^{2}

x \to 4 lim (\frac{9}{x})

\frac{2 s}{( s ^{2} + 25 ) ( s - 1 )}

y = \frac{2 x}{x ^{2} - 1}

y (θ) = e^{t a n (θ)}

What is the integral of (1-x)/(x^3) ?
The integral of (1-x)/(x^3) is -1/(2x^2)+1/x+C