What is the integral from 1 to 4 of 1/(x^2) ?

The integral from 1 to 4 of 1/(x^2) is 3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of 1/(x^2)

\int_{1}^{4} \frac{1}{x ^{2}} d x

\frac{3}{4}

Decimal

0.75

Solution steps

\int_{1}^{4} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{4}

= [- \frac{1}{x}]_{1}^{4}

Compute the boundaries:

\frac{3}{4}

= \frac{3}{4}

\frac{d}{d x} (sin (x) - \frac{1}{18} sin (3 x))

\frac{1}{( 1 + x ^{2} )}

\frac{d}{d x} ((x + 2)^{2 x - 3})

\frac{d}{d t} (e^{- i t})

x \to 6 lim (c x^{2} + 9 x)

What is the integral from 1 to 4 of 1/(x^2) ?
The integral from 1 to 4 of 1/(x^2) is 3/4