What is area sin^2(x),sin^4(x),[0,pi] ?

The answer to area sin^2(x),sin^4(x),[0,pi] is pi/8

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area sin^2(x),sin^4(x),[0,pi]

area

sin^{2} (x), sin^{4} (x), [0, π]

\frac{π}{8}

Decimal

0.39269 \dots

Solution steps

Apply the area formula:

\int_{0}^{π} ∣ cos (x) ∣^{2} ∣ sin (x) ∣^{2} d x

Solve

\int_{0}^{π} ∣ cos (x) ∣^{2} ∣ sin (x) ∣^{2} d x : \frac{π}{8}

The area is:

= \frac{π}{8}

\int (4 x + 1) x - 5 d x

\frac{d y}{d x} = 3 cos (7 x)

g (x) = x + 5

\int 4 x - 2 x d x

\int e^{2} ln (x) d x

What is area sin^2(x),sin^4(x),[0,pi] ?
The answer to area sin^2(x),sin^4(x),[0,pi] is pi/8