What is (\partial)/(\partial x)(7ye^{5x}) ?

The answer to (\partial)/(\partial x)(7ye^{5x}) is 35e^{5x}y

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(\partial)/(\partial x)(7ye^{5x})

\frac{\partial}{\partial x} (7 y e^{5 x})

35 e^{5 x} y

Solution steps

\frac{\partial}{\partial x} (7 y e^{5 x})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 y \frac{\partial}{\partial x} (e^{5 x})

Apply the chain rule:

e^{5 x} \frac{\partial}{\partial x} (5 x)

= e^{5 x} \frac{\partial}{\partial x} (5 x)

\frac{\partial}{\partial x} (5 x) = 5

= 7 y e^{5 x} \cdot 5

Simplify

= 35 e^{5 x} y

y = ln (x), y = 0, x = 4 e

sin (a x)

\int \frac{( 1 - 3 x )}{2 x - 3 x ^{2}} d x

\frac{d}{d x} (- \frac{2}{x ^{2} + 1})

\frac{d y}{d x} = \frac{( x - 3 )}{( y + 1 )}

What is (\partial)/(\partial x)(7ye^{5x}) ?
The answer to (\partial)/(\partial x)(7ye^{5x}) is 35e^{5x}y