What is the tangent of f(x)=5sin(x)-3cos(x),\at x=pi ?

The tangent of f(x)=5sin(x)-3cos(x),\at x=pi is y=-5x+3+5pi

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tangent of f(x)=5sin(x)-3cos(x),\at x=pi

tangent of

f (x) = 5 sin (x) - 3 cos (x), at x = π

y = - 5 x + 3 + 5 π

Solution steps

Find the tangent point:

(π, 3)

Find the slope of

f (x) = 5 sin (x) - 3 cos (x) : \frac{df ( x )}{d x} = 5 cos (x) + 3 sin (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 5

Find the line with slope m=

- 5

and passing through

(π, 3) : y = - 5 x + 3 + 5 π

y = - 5 x + 3 + 5 π

\int 5 x e^{8 x} d x

\int \frac{e ^{x}}{e ^{x} + 2} d x

\frac{d}{d x} (\frac{5 - 3 x}{x ^{2} + 3 x})

cos (\frac{π x}{2})

\int_{0}^{1} 4 x arccos (x) d x

What is the tangent of f(x)=5sin(x)-3cos(x),\at x=pi ?
The tangent of f(x)=5sin(x)-3cos(x),\at x=pi is y=-5x+3+5pi