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Popular >

integral from 1 to 2 of (x^2+2x)

Solution

\int_{1}^{2} (x^{2} + 2 x) d x

Solution

\frac{16}{3}

+1

Decimal

5.33333 \dots

Solution steps

\int_{1}^{2} x^{2} + 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{2} d x + \int_{1}^{2} 2 x d x

\int_{1}^{2} x^{2} d x = \frac{7}{3}

\int_{1}^{2} 2 x d x = 3

= \frac{7}{3} + 3

Simplify

\frac{7}{3} + 3 : \frac{16}{3}

= \frac{16}{3}

Graph

Popular Examples

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f (x) = x^{2} + x, at x = - 1, 2

integral from-2 to 1 of (x^2-6x+12)

\int_{- 2}^{1} (x^{2} - 6 x + 12) d x

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\frac{d}{d x} (\frac{x}{( 3 x - 2 ) ^{4}})

integral of (sec^2(x)+7)

\int (sec^{2} (x) + 7) d x

tangent of f(x)=-3x^4,\at x=-1 tangent of

f (x) = - 3 x^{4}, at x = - 1

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (x^2+2x) ?
The integral from 1 to 2 of (x^2+2x) is 16/3