What is the solution for y^{''}+10y+25y=0 ?

The solution for y^{''}+10y+25y=0 is y=c_{1}cos(sqrt(35)t)+c_{2}sin(sqrt(35)t)

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y^{''}+10y+25y=0

y^{^{''}} + 10 y + 25 y = 0

y = c_{1} cos (35 t) + c_{2} sin (35 t)

Solution steps

y^{''} (t) + 10 y + 25 y = 0

Solve linear ODE:

y = c_{1} cos (35 t) + c_{2} sin (35 t)

y = c_{1} cos (35 t) + c_{2} sin (35 t)

\frac{\partial}{\partial x} (\frac{ln ( x )}{x ^{2}})

x y^{^{'}} + y = 3 cos (x), y (π) = 0

\frac{\partial}{\partial x} (e^{x} - x (sin (y)))

\frac{6 x ^{2} + 4 x + 2}{x}

\frac{d}{d x} (- x - 1)

What is the solution for y^{''}+10y+25y=0 ?
The solution for y^{''}+10y+25y=0 is y=c_{1}cos(sqrt(35)t)+c_{2}sin(sqrt(35)t)