What is the derivative of (x^3+2/3) ?

The derivative of (x^3+2/3) is x^2

What is the first derivative of (x^3+2/3) ?

The first derivative of (x^3+2/3) is x^2

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\frac{d}{d x} (\frac{x ^{3} + 2}{3})

x^{2}

Solution steps

\frac{d}{d x} (\frac{x ^{3} + 2}{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d x} (x^{3} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{3} (\frac{d}{d x} (x^{3}) + \frac{d}{d x} (2))

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2) = 0

= \frac{1}{3} (3 x^{2} + 0)

Simplify

\frac{1}{3} (3 x^{2} + 0) : x^{2}

= x^{2}

\int e^{6 x} cos (2 x) d x

\frac{d}{d x} (\frac{4}{4 x})

y^{^{''}} + 2 y^{^{'}} + 1 y = 0

\frac{\partial}{\partial y} (\frac{x}{( 1 + 2 x + 3 y )})

2 y^{^{''}} - 9 y^{^{'}} + 4 y = 0

What is the derivative of (x^3+2/3) ?
The derivative of (x^3+2/3) is x^2
What is the first derivative of (x^3+2/3) ?
The first derivative of (x^3+2/3) is x^2