What is the integral from 1 to 5 of 4/(x^2) ?

The integral from 1 to 5 of 4/(x^2) is 16/5

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integral from 1 to 5 of 4/(x^2)

\int_{1}^{5} \frac{4}{x ^{2}} d x

\frac{16}{5}

Decimal

3.2

Solution steps

\int_{1}^{5} \frac{4}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{1}^{5} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{5}

= 4 [- \frac{1}{x}]_{1}^{5}

Compute the boundaries:

\frac{4}{5}

= 4 \cdot \frac{4}{5}

Simplify

= \frac{16}{5}

\frac{d}{d y} (arctan (y))

\int tan (g) (x) d x

\int cosh (t) d t

\frac{x + 5}{x + 1}

\int 8 x^{3} + 5 d x

What is the integral from 1 to 5 of 4/(x^2) ?
The integral from 1 to 5 of 4/(x^2) is 16/5