What is area x^2+4x-5,-x^2+4x+3 ?

The answer to area x^2+4x-5,-x^2+4x+3 is 64/3

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area x^2+4x-5,-x^2+4x+3

area

x^{2} + 4 x - 5, - x^{2} + 4 x + 3

\frac{64}{3}

Decimal

21.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} x^{2} + 4 x - 5 - (- x^{2} + 4 x + 3) d x

Solve

\int_{- 2}^{2} x^{2} + 4 x - 5 - (- x^{2} + 4 x + 3) d x : \frac{64}{3}

The area is:

= \frac{64}{3}

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\frac{\partial}{\partial y} (x^{2} + x y + 3 x + 2 y + 5)