What is the derivative of 1/(4s^3) ?

The derivative of 1/(4s^3) is -3/(4s^4)

What is the first derivative of 1/(4s^3) ?

The first derivative of 1/(4s^3) is -3/(4s^4)

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derivative of

\frac{1}{4 s ^{3}}

- \frac{3}{4 s ^{4}}

Solution steps

\frac{d}{d s} (\frac{1}{4 s ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} \frac{d}{d s} (\frac{1}{s ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{4} \frac{d}{d s} (s^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{4} (- 3 s^{- 3 - 1})

Simplify

\frac{1}{4} (- 3 s^{- 3 - 1}) : - \frac{3}{4 s ^{4}}

= - \frac{3}{4 s ^{4}}

\frac{\partial}{\partial x} (1 - x^{2} - x - 3 y^{2} + y)

\frac{\partial}{\partial x} (x y - 4 x^{2} y)

y^{^{'}} = 4 y + x^{2} + 9

\int (3^{x} - sec^{2} (x)) d x

\frac{d y}{d x} = - 4 x + 6 x^{2}

What is the derivative of 1/(4s^3) ?
The derivative of 1/(4s^3) is -3/(4s^4)
What is the first derivative of 1/(4s^3) ?
The first derivative of 1/(4s^3) is -3/(4s^4)