What is the integral from-6 to 6 of 1/v ?

The integral from-6 to 6 of 1/v is diverges

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integral from-6 to 6 of 1/v

\int_{- 6}^{6} \frac{1}{v} d v

diverges

Solution steps

\int_{- 6}^{6} \frac{1}{v} d v

Find undefined (singularity) points:

v = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 6}^{0} \frac{1}{v} d v + \int_{0}^{6} \frac{1}{v} d v

\int_{- 6}^{0} \frac{1}{v} d v =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

y = ln (2^{3})

\frac{d}{d x} (\frac{x ^{2}}{sin ( x )})

n = 1 \sum \infty (3 n) x^{n}

\frac{\partial}{\partial x} (9 x y^{2})

\int_{0}^{2} (1 - 2 x) d x

What is the integral from-6 to 6 of 1/v ?
The integral from-6 to 6 of 1/v is diverges