What is the solution for x^2ln(x/y)dy+xydx=0 ?

The solution for x^2ln(x/y)dy+xydx=0 is y=-(c_{1})/(\W(-\frac{c_{1)}{ex})}

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x^2ln(x/y)dy+xydx=0

x^{2} ln (\frac{x}{y}) d y + x y d x = 0

y = - \frac{c _{1}}{W ( - \frac{c _{1}}{e x} )}

Solution steps

x^{2} ln (\frac{x}{y}) d y + x y d x = 0

Solve using substitution:

y = - \frac{c _{1}}{W ( - \frac{c _{1}}{e x} )}

y = - \frac{c _{1}}{W ( - \frac{c _{1}}{e x} )}

\frac{\partial}{\partial x} (sin (x e^{x y}))

y^{^{''}} - y^{^{'}} + \frac{1}{4} y = 2 + e^{\frac{x}{2}}

\int \frac{3 - x}{x ^{3} + 4 x ^{2} + 3 x} d x

\frac{d}{d x} (4 ln (cos (x)))

x \to 3 - lim (2 x - 1)

What is the solution for x^2ln(x/y)dy+xydx=0 ?
The solution for x^2ln(x/y)dy+xydx=0 is y=-(c_{1})/(\W(-\frac{c_{1)}{ex})}