What is the tangent of f(x)=3x(x^2-4x+5)^6,\at x=2 ?

The tangent of f(x)=3x(x^2-4x+5)^6,\at x=2 is y=3x

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tangent of f(x)=3x(x^2-4x+5)^6,\at x=2

tangent of

f (x) = 3 x (x^{2} - 4 x + 5)^{6}, at x = 2

y = 3 x

Solution steps

Find the tangent point:

(2, 6)

Find the slope of

f (x) = 3 x (x^{2} - 4 x + 5)^{6} : \frac{df ( x )}{d x} = 3 ((x^{2} - 4 x + 5)^{6} + 6 x (x^{2} - 4 x + 5)^{5} (2 x - 4))

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3

Find the line with slope m=

3

and passing through

(2, 6) : y = 3 x

y = 3 x

\int \frac{e ^{u}}{( 9 - e ^{u} ) ^{2}} d u

\int \frac{( 26 x + 4 )}{( 5 x + 1 ) ( x - 1 )} d x

\int \frac{1}{3 x - 1} d x

\frac{5}{s ^{2} + 25}

\frac{\partial}{\partial x} (\frac{x - 7 y}{y ^{2} + 6 x ^{2}})

What is the tangent of f(x)=3x(x^2-4x+5)^6,\at x=2 ?
The tangent of f(x)=3x(x^2-4x+5)^6,\at x=2 is y=3x