What is (\partial)/(\partial x)(y^2-x^2) ?

The answer to (\partial)/(\partial x)(y^2-x^2) is -2x

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(\partial)/(\partial x)(y^2-x^2)

\frac{\partial}{\partial x} (y^{2} - x^{2})

- 2 x

Solution steps

\frac{\partial}{\partial x} (y^{2} - x^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y^{2}) - \frac{\partial}{\partial x} (x^{2})

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

= 0 - 2 x

Simplify

= - 2 x

ln (cos (x))

d y = (x - 2 y (cot (2 x))) d x

\frac{d}{d x} (lo g_{10} (1 + x))

\frac{d}{d x} (tan (x) + 3 co tan (x))

\int (x^{\frac{3}{2}}) d x

What is (\partial)/(\partial x)(y^2-x^2) ?
The answer to (\partial)/(\partial x)(y^2-x^2) is -2x