What is the derivative of 1-3/(x+7) ?

The derivative of 1-3/(x+7) is 3/((x+7)^2)

What is the first derivative of 1-3/(x+7) ?

The first derivative of 1-3/(x+7) is 3/((x+7)^2)

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\frac{d}{d x} (1 - \frac{3}{x + 7})

\frac{3}{( x + 7 ) ^{2}}

Solution steps

\frac{d}{d x} (1 - \frac{3}{x + 7})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (\frac{3}{x + 7})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{3}{x + 7}) = - \frac{3}{( x + 7 ) ^{2}}

= 0 - (- \frac{3}{( x + 7 ) ^{2}})

Simplify

= \frac{3}{( x + 7 ) ^{2}}

\frac{d}{d x} (cos (e^{3 x}))

\int_{1}^{5} 2 x + 1 d x

\frac{4 x ^{2} + 4 x + 2}{x}

\int \frac{( x ^{3} + x )}{1 - x ^{4} - x ^{2}} d x

x \to 2 lim (2 x^{2} - 4 x + 3)

What is the derivative of 1-3/(x+7) ?
The derivative of 1-3/(x+7) is 3/((x+7)^2)
What is the first derivative of 1-3/(x+7) ?
The first derivative of 1-3/(x+7) is 3/((x+7)^2)