What is the integral of 3x^4+2x^2-x/2 ?

The integral of 3x^4+2x^2-x/2 is (3x^5)/5+(2x^3)/3-(x^2)/4+C

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integral of 3x^4+2x^2-x/2

\int 3 x^{4} + 2 x^{2} - \frac{x}{2} d x

\frac{3 x ^{5}}{5} + \frac{2 x ^{3}}{3} - \frac{x ^{2}}{4} + C

Solution steps

\int 3 x^{4} + 2 x^{2} - \frac{x}{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{4} d x + \int 2 x^{2} d x - \int \frac{x}{2} d x

\int 3 x^{4} d x = \frac{3 x ^{5}}{5}

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= \frac{3 x ^{5}}{5} + \frac{2 x ^{3}}{3} - \frac{x ^{2}}{4}

Add a constant to the solution

= \frac{3 x ^{5}}{5} + \frac{2 x ^{3}}{3} - \frac{x ^{2}}{4} + C

\int_{0}^{- 0.6} 150 x d x

x \to - 2 lim ((x^{2} + 5))

\int \frac{- 2}{x} d x

\int_{- \infty}^{0} \frac{1}{9 + x ^{2}} d x

(- 1, 4), (5, - 1)

What is the integral of 3x^4+2x^2-x/2 ?
The integral of 3x^4+2x^2-x/2 is (3x^5)/5+(2x^3)/3-(x^2)/4+C