What is the tangent of y=x^2-4x+4,(3,1) ?

The tangent of y=x^2-4x+4,(3,1) is y=2x-5

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tangent of y=x^2-4x+4,(3,1)

tangent of

y = x^{2} - 4 x + 4, (3, 1)

y = 2 x - 5

Solution steps

Find the slope of

y = x^{2} - 4 x + 4 : \frac{d y}{d x} = 2 x - 4

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(3, 1) : y = 2 x - 5

y = 2 x - 5

x y^{^{'}} + 2 y^{^{'}} - (x + 2) cos (x) + y = 0

n = 0 \sum \infty 2 (- \frac{1}{2})^{n}

x \to 0 lim (sin (x^{2}))

\frac{\partial}{\partial x} (2 x arctan (\frac{x}{y}))

ln (x^{2} + 2)

What is the tangent of y=x^2-4x+4,(3,1) ?
The tangent of y=x^2-4x+4,(3,1) is y=2x-5