What is area x=-2,x=3,y=x^2-3,y=2x ?

The answer to area x=-2,x=3,y=x^2-3,y=2x is 13

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area x=-2,x=3,y=x^2-3,y=2x

area

x = - 2, x = 3, y = x^{2} - 3, y = 2 x

13

Solution steps

Apply the area formula:

\int_{- 2}^{3} x^{2} - 3 - 2 x d x

Solve

\int_{- 2}^{3} x^{2} - 3 - 2 x d x : 13

The area is:

= 13

e^{5 x + 5}, 0

\frac{d y}{d x} = (1 - 2 x) y^{2}

\int_{0}^{2} 2 π x (3 + \frac{x ^{2}}{3}) d x

f (x) = \frac{sin ( x ) + cos ( x )}{sin ( x ) - cos ( x )}

(1 + x^{3}) d y - x^{2} y d x = 0

What is area x=-2,x=3,y=x^2-3,y=2x ?
The answer to area x=-2,x=3,y=x^2-3,y=2x is 13