What is the derivative of x^3-9x^2+24x ?

The derivative of x^3-9x^2+24x is 3x^2-18x+24

What is the first derivative of x^3-9x^2+24x ?

The first derivative of x^3-9x^2+24x is 3x^2-18x+24

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\frac{d}{d x} (x^{3} - 9 x^{2} + 24 x)

3 x^{2} - 18 x + 24

Solution steps

\frac{d}{d x} (x^{3} - 9 x^{2} + 24 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (9 x^{2}) + \frac{d}{d x} (24 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (9 x^{2}) = 18 x

\frac{d}{d x} (24 x) = 24

= 3 x^{2} - 18 x + 24

n = 1 \sum \infty \frac{2 ^{n}}{n ^{2}}

\frac{1}{2 x} - \frac{5}{3 x ^{2}}

\int 11 arcsin (2 x) d x

\int (e^{- 10 x}) d x

x \to 0 lim (\frac{x 4 ^{x}}{4 ^{x} - 1})

What is the derivative of x^3-9x^2+24x ?
The derivative of x^3-9x^2+24x is 3x^2-18x+24
What is the first derivative of x^3-9x^2+24x ?
The first derivative of x^3-9x^2+24x is 3x^2-18x+24