What is the derivative of f(x)=sqrt(3x+1) ?

The derivative of f(x)=sqrt(3x+1) is 3/(2sqrt(3x+1))

What is the first derivative of f(x)=sqrt(3x+1) ?

The first derivative of f(x)=sqrt(3x+1) is 3/(2sqrt(3x+1))

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derivative of

f (x) = 3 x + 1

\frac{3}{2 3 x + 1}

Solution steps

\frac{d}{d x} (3 x + 1)

Apply the chain rule:

\frac{1}{2 3 x + 1} \frac{d}{d x} (3 x + 1)

= \frac{1}{2 3 x + 1} \frac{d}{d x} (3 x + 1)

\frac{d}{d x} (3 x + 1) = 3

= \frac{1}{2 3 x + 1} \cdot 3

Simplify

\frac{1}{2 3 x + 1} \cdot 3 : \frac{3}{2 3 x + 1}

= \frac{3}{2 3 x + 1}

\frac{\partial}{\partial x} (10)

\frac{\partial}{\partial y} (x^{2} + 2 y^{2} + 3 x z)

x \to - 2 lim (\frac{1}{x + 1})

\int \frac{4}{x ln ( 5 x )} d x

\int \frac{1}{( 441 + x ^{2} ) ^{\frac{3}{2}}} d x

What is the derivative of f(x)=sqrt(3x+1) ?
The derivative of f(x)=sqrt(3x+1) is 3/(2sqrt(3x+1))
What is the first derivative of f(x)=sqrt(3x+1) ?
The first derivative of f(x)=sqrt(3x+1) is 3/(2sqrt(3x+1))