What is the derivative of-y+x+2 ?

The derivative of-y+x+2 is -(dy)/(dx)+1

What is the first derivative of-y+x+2 ?

The first derivative of-y+x+2 is -(dy)/(dx)+1

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\frac{d}{d x} (- y + x + 2)

- \frac{d y}{d x} + 1

Solution steps

\frac{d}{d x} (- y + x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d y}{d x} + \frac{d x}{d x} + \frac{d}{d x} (2)

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= - \frac{d y}{d x} + 1 + 0

Simplify

= - \frac{d y}{d x} + 1

\int \frac{sec ^{2} ( x )}{2 x} d x

(x - 1) \cdot ln (x - 1)

x \to 0 lim (\frac{x ^{3} + 3 x}{x})

\int tan^{3} (θ) sec^{2} (θ) d θ

\int \frac{3}{5} - \frac{6}{x} d x

What is the derivative of-y+x+2 ?
The derivative of-y+x+2 is -(dy)/(dx)+1
What is the first derivative of-y+x+2 ?
The first derivative of-y+x+2 is -(dy)/(dx)+1