What is the derivative of 18xe^x ?

The derivative of 18xe^x is 18(e^x+e^xx)

What is the first derivative of 18xe^x ?

The first derivative of 18xe^x is 18(e^x+e^xx)

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\frac{d}{d x} (18 x e^{x})

18 (e^{x} + e^{x} x)

Solution steps

\frac{d}{d x} (18 x e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 18 \frac{d}{d x} (x e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x}

= 18 (\frac{d x}{d x} e^{x} + \frac{d}{d x} (e^{x}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= 18 (1 \cdot e^{x} + e^{x} x)

Simplify

= 18 (e^{x} + e^{x} x)

\frac{\partial}{\partial x} (\frac{x + 4}{y + 3})

144 (\frac{216}{x ^{2}} + \frac{x}{x + 24})

y^{^{'}} = e^{x} y^{7} + 2 y

\int \frac{ln ( x + 1 )}{x + 1} d x

\frac{d y}{d t} = sin (2 π (t + 3))

What is the derivative of 18xe^x ?
The derivative of 18xe^x is 18(e^x+e^xx)
What is the first derivative of 18xe^x ?
The first derivative of 18xe^x is 18(e^x+e^xx)