What is the derivative of-(0.1x-23)^2 ?

The derivative of-(0.1x-23)^2 is -0.02x+4.6

What is the first derivative of-(0.1x-23)^2 ?

The first derivative of-(0.1x-23)^2 is -0.02x+4.6

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derivative of

- (0.1 x - 23)^{2}

- 0.02 x + 4.6

Solution steps

\frac{d}{d x} (- (0.1 x - 23)^{2})

Simplify

- (0.1 x - 23)^{2} : - 0.01 x^{2} + 4.6 x - 529

= \frac{d}{d x} (- 0.01 x^{2} + 4.6 x - 529)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (0.01 x^{2}) + \frac{d}{d x} (4.6 x) - \frac{d}{d x} (529)

\frac{d}{d x} (0.01 x^{2}) = 0.02 x

\frac{d}{d x} (4.6 x) = 4.6

\frac{d}{d x} (529) = 0

= - 0.02 x + 4.6 - 0

Simplify

= - 0.02 x + 4.6

\int 2 e^{- 3 t} d t

4 x + 3

(- 4, 2), (6, - 3)

\frac{d}{d x} (\frac{1}{1 + e ^{4 x}})

x \to 0 + lim (\frac{x + ∣ x ∣}{x})

What is the derivative of-(0.1x-23)^2 ?
The derivative of-(0.1x-23)^2 is -0.02x+4.6
What is the first derivative of-(0.1x-23)^2 ?
The first derivative of-(0.1x-23)^2 is -0.02x+4.6