What is the integral of sec^5(x) ?

The integral of sec^5(x) is (sec^4(x)sin(x))/4+3/4 (1/2 sec(x)tan(x)+1/2 ln|tan(x)+sec(x)|)+C

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integral of sec^5(x)

\int sec^{5} (x) d x

\frac{sec ^{4} ( x ) sin ( x )}{4} + \frac{3}{4} (\frac{1}{2} sec (x) tan (x) + \frac{1}{2} ln ∣ tan (x) + sec (x) ∣) + C

Solution steps

\int sec^{5} (x) d x

Apply Integral Reduction

= \frac{sec ^{4} ( x ) sin ( x )}{4} + \frac{3}{4} \cdot \int sec^{3} (x) d x

\int sec^{3} (x) d x = \frac{1}{2} sec (x) tan (x) + \frac{1}{2} ln ∣ tan (x) + sec (x) ∣

= \frac{sec ^{4} ( x ) sin ( x )}{4} + \frac{3}{4} (\frac{1}{2} sec (x) tan (x) + \frac{1}{2} ln ∣ tan (x) + sec (x) ∣)

Add a constant to the solution

= \frac{sec ^{4} ( x ) sin ( x )}{4} + \frac{3}{4} (\frac{1}{2} sec (x) tan (x) + \frac{1}{2} ln ∣ tan (x) + sec (x) ∣) + C

f (x) = x x, at x = 0

\int \frac{1}{x ^{2} + 8 x + 32} d x

x \to 7 - lim (\frac{x}{x ^{2} - 49})

x + 1, 9 - x^{2}, - 1, 2

y^{^{'}} = (x + y)^{2} - 1, y (1) = 6

What is the integral of sec^5(x) ?
The integral of sec^5(x) is (sec^4(x)sin(x))/4+3/4 (1/2 sec(x)tan(x)+1/2 ln|tan(x)+sec(x)|)+C