What is (\partial)/(\partial x)(sqrt(x+yz)) ?

The answer to (\partial)/(\partial x)(sqrt(x+yz)) is 1/(2sqrt(x+yz))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(sqrt(x+yz))

\frac{\partial}{\partial x} (x + yz)

\frac{1}{2 x + yz}

Solution steps

\frac{\partial}{\partial x} (x + yz)

Treat

y, z

as constants

Apply the chain rule:

\frac{1}{2 x + yz} \frac{\partial}{\partial x} (x + yz)

= \frac{1}{2 x + yz} \frac{\partial}{\partial x} (x + yz)

\frac{\partial}{\partial x} (x + yz) = 1

= \frac{1}{2 x + yz} \cdot 1

Simplify

= \frac{1}{2 x + yz}

\int_{1}^{2} \frac{13}{x ^{3} + 2 x} d x

\int \frac{2 x + 1}{x} d x

\frac{\partial}{\partial x} (e^{x y} cos (x^{2}))

x y^{2} d y = (y^{3} - x^{3}) d x

\frac{d}{d θ} (1 + sin (2 θ))

What is (\partial)/(\partial x)(sqrt(x+yz)) ?
The answer to (\partial)/(\partial x)(sqrt(x+yz)) is 1/(2sqrt(x+yz))