What is the solution for y^{''}+3y=x ?

The solution for y^{''}+3y=x is y=c_{1}cos(sqrt(3)x)+c_{2}sin(sqrt(3)x)+x/3

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y^{''}+3y=x

y^{^{''}} + 3 y = x

y = c_{1} cos (3 x) + c_{2} sin (3 x) + \frac{x}{3}

Solution steps

y^{''} (x) + 3 y = x

Solve linear ODE:

y = c_{1} cos (3 x) + c_{2} sin (3 x) + \frac{x}{3}

y = c_{1} cos (3 x) + c_{2} sin (3 x) + \frac{x}{3}

\int t ln (t + 3) d t

\int \frac{1}{b} sin (b x) d x

\int (2 x - 1)^{6} d x

\int \frac{2 ln ( x )}{x ^{2}} d x

y = x^{2} - 9 x, (7, - 14)

What is the solution for y^{''}+3y=x ?
The solution for y^{''}+3y=x is y=c_{1}cos(sqrt(3)x)+c_{2}sin(sqrt(3)x)+x/3