What is derivative of f(x)=(1-3t)/(2+t) ?

The answer to derivative of f(x)=(1-3t)/(2+t) is (dt)/(dx)=0

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derivative of f(x)=(1-3t)/(2+t)

derivative of

f (x) = \frac{1 - 3 t}{2 + t}

\frac{d t}{d x} = 0

Solution steps

f (x) = \frac{1 - 3 t}{2 + t}

Treat

t

t (x)

Differentiate both sides:

0 = - \frac{7 \frac{d t}{d x}}{( 2 + t ) ^{2}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\int (- 3 x + 2) \cdot e^{- x} d x

\frac{\partial}{\partial y} (\frac{x}{x ^{2} + y ^{2}} + x)

\frac{\partial}{\partial x} (x (x + y) 2)

\int e^{x} \cdot cos (x) d x

x \to 0 + lim (x^{2} + 5)

What is derivative of f(x)=(1-3t)/(2+t) ?
The answer to derivative of f(x)=(1-3t)/(2+t) is (dt)/(dx)=0