What is the integral of 3x^2cos(x) ?

The integral of 3x^2cos(x) is 3(x^2sin(x)-2(-xcos(x)+sin(x)))+C

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integral of 3x^2cos(x)

\int 3 x^{2} cos (x) d x

3 (x^{2} sin (x) - 2 (- x cos (x) + sin (x))) + C

Solution steps

\int 3 x^{2} cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int x^{2} cos (x) d x

Apply Integration By Parts

: x^{2} sin (x) - \int 2 x sin (x) d x

= 3 (x^{2} sin (x) - \int 2 x sin (x) d x)

\int 2 x sin (x) d x = 2 (- x cos (x) + sin (x))

= 3 (x^{2} sin (x) - 2 (- x cos (x) + sin (x)))

Add a constant to the solution

= 3 (x^{2} sin (x) - 2 (- x cos (x) + sin (x))) + C

n = 0 \sum \infty \frac{n !}{10 7 ^{n}}

\frac{d}{d x} (\frac{x ^{2}}{5 x + 2})

3 t^{2} - 30 t + 72

f (x) = \frac{8}{x}

x \to - 1 + lim (\frac{2 x}{x + 1})

What is the integral of 3x^2cos(x) ?
The integral of 3x^2cos(x) is 3(x^2sin(x)-2(-xcos(x)+sin(x)))+C