What is the derivative of (x^2/((x-1))) ?

The derivative of (x^2/((x-1))) is (x^2-2x)/((x-1)^2)

What is the first derivative of (x^2/((x-1))) ?

The first derivative of (x^2/((x-1))) is (x^2-2x)/((x-1)^2)

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\frac{d}{d x} (\frac{x ^{2}}{( x - 1 )})

\frac{x ^{2} - 2 x}{( x - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{( x - 1 )})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( x - 1 ) - \frac{d}{d x} ( x - 1 ) x ^{2}}{( x - 1 ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x - 1) = 1

= \frac{2 x ( x - 1 ) - 1 \cdot x ^{2}}{( x - 1 ) ^{2}}

Simplify

\frac{2 x ( x - 1 ) - 1 \cdot x ^{2}}{( x - 1 ) ^{2}} : \frac{x ^{2} - 2 x}{( x - 1 ) ^{2}}

= \frac{x ^{2} - 2 x}{( x - 1 ) ^{2}}

\int x^{2} + 6 e^{x} + C d x

\int e x d x

\int \frac{sin ( 2 x )}{1 - sin ^{2} ( x )} d x

y^{^{''}} - y = \frac{e ^{x}}{e ^{x}}

\int_{1}^{2} 4 - x^{2} d x

What is the derivative of (x^2/((x-1))) ?
The derivative of (x^2/((x-1))) is (x^2-2x)/((x-1)^2)
What is the first derivative of (x^2/((x-1))) ?
The first derivative of (x^2/((x-1))) is (x^2-2x)/((x-1)^2)