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Popular >

integral of 1/(e^v)

Solution

\int \frac{1}{e ^{v}} d v

Solution

- \frac{1}{e ^{v}} + C

Solution steps

\int \frac{1}{e ^{v}} d v

Apply u-substitution

: \int \frac{1}{u ^{2}} d u

= \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= - \frac{1}{u}

Substitute back

u = e^{v}

= - \frac{1}{e ^{v}}

Add a constant to the solution

= - \frac{1}{e ^{v}} + C

Graph

Popular Examples

(\partial)/(\partial y)((x^2+y^2)/(x+y))

\frac{\partial}{\partial y} (\frac{x ^{2} + y ^{2}}{x + y})

integral of 2x^{2x}(ln(x)+1)

\int 2 x^{2 x} (ln (x) + 1) d x

derivative of e^{(-x/y})

\frac{d}{d x} (e^{\frac{- x}{y}})

integral from 2 to 5 of 1/(x+1)

\int_{2}^{5} \frac{1}{x + 1} d x

(\partial)/(\partial x)(x/(x^2+2y^2))

\frac{\partial}{\partial x} (\frac{x}{x ^{2} + 2 y ^{2}})

Frequently Asked Questions (FAQ)

What is the integral of 1/(e^v) ?
The integral of 1/(e^v) is -1/(e^v)+C