What is the integral of (3x^2-2x+1) ?

The integral of (3x^2-2x+1) is x^3-x^2+x+C

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integral of (3x^2-2x+1)

\int (3 x^{2} - 2 x + 1) d x

x^{3} - x^{2} + x + C

Solution steps

\int 3 x^{2} - 2 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x - \int 2 x d x + \int 1 d x

\int 3 x^{2} d x = x^{3}

\int 2 x d x = x^{2}

\int 1 d x = x

= x^{3} - x^{2} + x

Add a constant to the solution

= x^{3} - x^{2} + x + C

\int \frac{x ^{2} - 1}{x} d x

f (x) = ln (1 + x^{2})

x \to 0 lim (sin (\frac{k x}{x}))

\int \frac{x}{2 x ^{2} + 5 x + 2} d x

x \to \infty lim (- 28 x^{4})

What is the integral of (3x^2-2x+1) ?
The integral of (3x^2-2x+1) is x^3-x^2+x+C