What is the derivative of e^{2x}+4 ?

The derivative of e^{2x}+4 is 2e^{2x}

What is the first derivative of e^{2x}+4 ?

The first derivative of e^{2x}+4 is 2e^{2x}

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\frac{d}{d x} (e^{2 x} + 4)

2 e^{2 x}

Solution steps

\frac{d}{d x} (e^{2 x} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{2 x}) + \frac{d}{d x} (4)

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

\frac{d}{d x} (4) = 0

= e^{2 x} \cdot 2 + 0

Simplify

= 2 e^{2 x}

\int_{0}^{4} (x + 3 x) d x

\int e^{x} e^{x} + 5 d x

\frac{d y}{d x} = (x + y)^{2}

f (x) = \frac{1}{2 x}, at x = 9

f (x) = (x^{4} - \frac{5}{x ^{3}})^{- 4}

What is the derivative of e^{2x}+4 ?
The derivative of e^{2x}+4 is 2e^{2x}
What is the first derivative of e^{2x}+4 ?
The first derivative of e^{2x}+4 is 2e^{2x}