What is the first (arctan(x))^' ?

The first (arctan(x))^' is 1/(x^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(arctan(x))^'

(arctan (x))^{^{'}}

\frac{1}{x ^{2} + 1}

Solution steps

(arctan (x))^{'}

Apply the common derivative:

(arctan (x))^{'} = \frac{1}{x ^{2} + 1}

= \frac{1}{x ^{2} + 1}

\frac{d y}{d x} = \frac{y}{x} + 3 x + 1

f (x) = \frac{x}{x ^{2} + 49}

\frac{d}{d x} (2 ln ∣ x - e^{x} ∣)

\frac{\partial}{\partial y} (- \frac{1}{ln ( 10 ) ( x - y )})

f (x) = \frac{8}{sin ( x ) + cos ( x )}