What is the tangent of f(x)=1+cos(x),\at x=(3pi)/2 ?

The tangent of f(x)=1+cos(x),\at x=(3pi)/2 is y=x+1-(3pi)/2

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tangent of f(x)=1+cos(x),\at x=(3pi)/2

tangent of

f (x) = 1 + cos (x), at x = \frac{3 π}{2}

y = x + 1 - \frac{3 π}{2}

Solution steps

Find the tangent point:

(\frac{3 π}{2}, 1)

Find the slope of

f (x) = 1 + cos (x) : \frac{df ( x )}{d x} = - sin (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

Find the line with slope m=

1

and passing through

(\frac{3 π}{2}, 1) : y = x + 1 - \frac{3 π}{2}

y = x + 1 - \frac{3 π}{2}

\int x^{4} e^{- 2 x} d x

\int_{- 4}^{2} x^{2} + 2 d x

\frac{d}{d x} (\frac{A x + B}{C x + d})

\int_{- 1}^{3} 3 x^{3} d x

\frac{d}{d x} (2 x^{2} - x^{4})

What is the tangent of f(x)=1+cos(x),\at x=(3pi)/2 ?
The tangent of f(x)=1+cos(x),\at x=(3pi)/2 is y=x+1-(3pi)/2