What is the limit as x approaches 3 of (x^2-9)/(x+2) ?

The limit as x approaches 3 of (x^2-9)/(x+2) is 0

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limit as x approaches 3 of (x^2-9)/(x+2)

x \to 3 lim (\frac{x ^{2} - 9}{x + 2})

0

Solution steps

x \to 3 lim (\frac{x ^{2} - 9}{x + 2})

Plug in the value

x = 3

= \frac{3 ^{2} - 9}{3 + 2}

Simplify

= 0

5 \cdot t^{3}

(1 + x^{2}) y^{^{''}} + 2 x y^{^{'}} - 2 y = 0

y^{^{'}} + y = 1.01 cos (10 x)

\int tan (7 x) (sec (7 x))^{2} d x

x \to 0 lim (\frac{3 x - 2}{9 x + 7})

What is the limit as x approaches 3 of (x^2-9)/(x+2) ?
The limit as x approaches 3 of (x^2-9)/(x+2) is 0