What is implicit (dy)/(dx),x+4y=1 ?

The answer to implicit (dy)/(dx),x+4y=1 is (dy)/(dx)=-1/4

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implicit (dy)/(dx),x+4y=1

implicit derivative

\frac{d y}{d x}, x + 4 y = 1

\frac{d y}{d x} = - \frac{1}{4}

Solution steps

x + 4 y = 1

Treat

y

y (x)

Differentiate both sides:

1 + 4 \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{1}{4}

\frac{d y}{d x} = - \frac{1}{4}

y^{^{''}} + 7 y^{^{'}} + 12 y = 0, y (0) = 1, y^{^{'}} (0) = 0

\int 18 sin^{3} (x co) s^{2} x

\int_{1}^{5} 8 x d x

\int_{2}^{x} cos (t) d t

x \to 2 lim (x^{2} + 4 x - 12)

What is implicit (dy)/(dx),x+4y=1 ?
The answer to implicit (dy)/(dx),x+4y=1 is (dy)/(dx)=-1/4