What is the derivative of sin^3(2x-1) ?

The derivative of sin^3(2x-1) is 6sin^2(2x-1)cos(2x-1)

What is the first derivative of sin^3(2x-1) ?

The first derivative of sin^3(2x-1) is 6sin^2(2x-1)cos(2x-1)

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\frac{d}{d x} (sin^{3} (2 x - 1))

6 sin^{2} (2 x - 1) cos (2 x - 1)

Solution steps

\frac{d}{d x} (sin^{3} (2 x - 1))

Apply the chain rule:

3 (sin (2 x - 1))^{2} \frac{d}{d x} (sin (2 x - 1))

= 3 (sin (2 x - 1))^{2} \frac{d}{d x} (sin (2 x - 1))

\frac{d}{d x} (sin (2 x - 1)) = cos (2 x - 1) \cdot 2

= 3 (sin (2 x - 1))^{2} cos (2 x - 1) \cdot 2

Simplify

= 6 sin^{2} (2 x - 1) cos (2 x - 1)

\int \frac{4 x ^{2} - 9 x + 1}{x ^{3} - 2 x ^{2} + x} d x

(x + 2)^{- 1}

x \to - 1 - lim (1)

\frac{5}{t}

\frac{d}{d x} (\frac{2 x ^{3} + 4}{x ^{2} + 1})

What is the derivative of sin^3(2x-1) ?
The derivative of sin^3(2x-1) is 6sin^2(2x-1)cos(2x-1)
What is the first derivative of sin^3(2x-1) ?
The first derivative of sin^3(2x-1) is 6sin^2(2x-1)cos(2x-1)