What is (\partial)/(\partial x)(3x+y^2) ?

The answer to (\partial)/(\partial x)(3x+y^2) is 3

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(\partial)/(\partial x)(3x+y^2)

\frac{\partial}{\partial x} (3 x + y^{2})

3

Solution steps

\frac{\partial}{\partial x} (3 x + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (3 x) = 3

\frac{\partial}{\partial x} (y^{2}) = 0

= 3 + 0

Simplify

= 3

\frac{d}{d x} (\frac{x}{a ^{2} - x ^{2}})

\frac{d}{d x} (x^{3} - 3 x^{2} + 3 x)

f (x) = x + e^{- 2 x}

6 sin (t)

x \to 0 lim (x (3 - cos (x^{2})))

What is (\partial)/(\partial x)(3x+y^2) ?
The answer to (\partial)/(\partial x)(3x+y^2) is 3