What is the derivative of g(x)=sqrt(2-x) ?

The derivative of g(x)=sqrt(2-x) is -1/(2sqrt(2-x))

What is the first derivative of g(x)=sqrt(2-x) ?

The first derivative of g(x)=sqrt(2-x) is -1/(2sqrt(2-x))

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derivative of

g (x) = 2 - x

- \frac{1}{2 2 - x}

Solution steps

\frac{d}{d x} (2 - x)

Apply the chain rule:

\frac{1}{2 2 - x} \frac{d}{d x} (2 - x)

= \frac{1}{2 2 - x} \frac{d}{d x} (2 - x)

\frac{d}{d x} (2 - x) = - 1

= \frac{1}{2 2 - x} (- 1)

Simplify

= - \frac{1}{2 2 - x}

f (x) = y^{\frac{2}{3}}

\int \frac{x ^{2} + 8 x + 4}{x ^{4} + 2 x ^{3} + x ^{2}} d x

15 sin (- π x) tan (\frac{2}{3} π x)

f (x) = 3 x^{2} - 6 x + 5

\int_{0}^{\frac{π}{2}} 7 sin^{2} (2 x) d x

What is the derivative of g(x)=sqrt(2-x) ?
The derivative of g(x)=sqrt(2-x) is -1/(2sqrt(2-x))
What is the first derivative of g(x)=sqrt(2-x) ?
The first derivative of g(x)=sqrt(2-x) is -1/(2sqrt(2-x))