What is the derivative of 2log_{6}(x) ?

The derivative of 2log_{6}(x) is 2/(ln(6)x)

What is the first derivative of 2log_{6}(x) ?

The first derivative of 2log_{6}(x) is 2/(ln(6)x)

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\frac{d}{d x} (2 lo g_{6} (x))

\frac{2}{ln ( 6 ) x}

Solution steps

\frac{d}{d x} (2 lo g_{6} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (lo g_{6} (x))

Apply the derivative log rule:

\frac{d}{d x} (lo g_{a} (x)) = \frac{1}{x ln ( a )}

= 2 \cdot \frac{1}{x ln ( 6 )}

Simplify

2 \cdot \frac{1}{x ln ( 6 )} : \frac{2}{ln ( 6 ) x}

= \frac{2}{ln ( 6 ) x}

y^{^{''}} + 3 y^{^{'}} + 2.25 y = 0

\frac{d}{d x} (5 e^{x} + \frac{4}{3 x})

\frac{d y}{d t} = 7 y^{2} t^{3}, y (2) = 3

\int_{1}^{3} \frac{t}{3 + t ^{2}} d t

\int \frac{2 x + 3}{x + 2} d x

What is the derivative of 2log_{6}(x) ?
The derivative of 2log_{6}(x) is 2/(ln(6)x)
What is the first derivative of 2log_{6}(x) ?
The first derivative of 2log_{6}(x) is 2/(ln(6)x)