What is the integral from 0 to 6 of-2x ?

The integral from 0 to 6 of-2x is -36

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 6 of-2x

\int_{0}^{6} - 2 x d x

- 36

Solution steps

\int_{0}^{6} - 2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int_{0}^{6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{6}

= - 2 [\frac{x ^{2}}{2}]_{0}^{6}

Compute the boundaries:

18

= - 2 \cdot 18

Simplify

= - 36

\frac{d}{d x} (\frac{2}{9} x^{3} + 3 x + cos (x) + 1)

\frac{\partial}{\partial x} (arcsin (2 x yz))

\int \frac{25}{x x} d x

\int \frac{3 x}{1 - 9 x ^{2}} d x

\frac{d}{d x} (\frac{1 - sin ( x )}{cos ( x )})