What is the derivative of f(x)=(66)/((1-x)^4) ?

The derivative of f(x)=(66)/((1-x)^4) is (264)/((1-x)^5)

What is the first derivative of f(x)=(66)/((1-x)^4) ?

The first derivative of f(x)=(66)/((1-x)^4) is (264)/((1-x)^5)

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derivative of

f (x) = \frac{66}{( 1 - x ) ^{4}}

\frac{264}{( 1 - x ) ^{5}}

Solution steps

\frac{d}{d x} (\frac{66}{( 1 - x ) ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 66 \frac{d}{d x} (\frac{1}{( 1 - x ) ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 66 \frac{d}{d x} ((1 - x)^{- 4})

Apply the chain rule:

- \frac{4}{( 1 - x ) ^{5}} \frac{d}{d x} (1 - x)

= - \frac{4}{( 1 - x ) ^{5}} \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= 66 (- \frac{4}{( 1 - x ) ^{5}} (- 1))

Simplify

66 (- \frac{4}{( 1 - x ) ^{5}} (- 1)) : \frac{264}{( 1 - x ) ^{5}}

= \frac{264}{( 1 - x ) ^{5}}

g (x) = sin (π) - 2

\frac{d x}{d t} = 5 \cdot 0.00001 - \frac{5 x}{10000}, x (0) = 2

\int 3 + 9 x^{2} d x

\int \frac{4}{sin ^{2} ( 2 x )} d x

x \to 2 lim (\frac{x}{x ^{2} + 4})

What is the derivative of f(x)=(66)/((1-x)^4) ?
The derivative of f(x)=(66)/((1-x)^4) is (264)/((1-x)^5)
What is the first derivative of f(x)=(66)/((1-x)^4) ?
The first derivative of f(x)=(66)/((1-x)^4) is (264)/((1-x)^5)